Linux查看当前登录用户并踢出用户的命令

　　1、查看当前登录用户

　　[wilsh@lcl ~]$ whatis w

　　w (1) – Show who is logged on and what they are doing

　　[wilsh@lcl ~]$ w

　　09:49:30 up 1 day, 17:19, 4 users, load average: 0.00, 0.00, 0.00

　　USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT

　　root tty3 – 09:25 23:25 0.10s 0.08s -bash

　　root pts/0 192.168.105.188 09:32 9:38 0.02s 0.02s -bash

　　root pts/1 192.168.105.188 09:36 9:32 0.03s 0.02s -bash

　　wilsh pts/2 192.168.105.188 09:41 0.00s 0.00s 0.00s w

　　2、踢出当前在线的用户

　　a)pkill

　　[wilsh@lcl ~]$ whatis pkill

　　pkill [pgrep] (1) – look up or signal processes based on name and other

　　attributes

　　[wilsh@lcl ~]$ pkill -KILL -u wilsh #-u用来指定用户名

　　[wilsh@lcl ~]$ pkill -9 -u wilsh # -KILL -9都是可以的。

　　[wilsh@lcl ~]$ pkill -KILL -t pts/2

　　[wilsh@lcl ~]$ whatis skill

　　skill

　　(1) – send a signal or report process status

　　[wilsh@lcl ~]$ skill -9 -t pts/2

　　[wilsh@lcl ~]$ w

　　09:57:37 up 1 day, 17:28, 4 users, load average: 0.00, 0.00, 0.00

　　USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT

　　root tty3 – 09:25 31:32 0.10s 0.08s -bash

　　root pts/0 192.168.105.188 09:32 17:45 0.02s 0.02s -bash

　　root pts/1 192.168.105.188 09:36 17:39 0.01s 0.01s -bash

　　wilsh pts/2 192.168.105.188 09:57 0.00s 0.00s 0.00s w

时间：(2024-02-07 14:20:35)
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